G(5x)=5x^2+4

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Solution for G(5x)=5x^2+4 equation: 



(5G)=5G^2+4

We move all terms to the left:

(5G)-(5G^2+4)=0

We get rid of parentheses

-5G^2+5G-4=0

a = -5; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·(-5)·(-4)
Δ = -55
Delta is less than zero, so there is no solution for the equation

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